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2y-4+2(2y+3)=-2(y+5)
We move all terms to the left:
2y-4+2(2y+3)-(-2(y+5))=0
We multiply parentheses
2y+4y-(-2(y+5))+6-4=0
We calculate terms in parentheses: -(-2(y+5)), so:We add all the numbers together, and all the variables
-2(y+5)
We multiply parentheses
-2y-10
Back to the equation:
-(-2y-10)
6y-(-2y-10)+2=0
We get rid of parentheses
6y+2y+10+2=0
We add all the numbers together, and all the variables
8y+12=0
We move all terms containing y to the left, all other terms to the right
8y=-12
y=-12/8
y=-1+1/2
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