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2y-3y-2y(y-6)=9
We move all terms to the left:
2y-3y-2y(y-6)-(9)=0
We add all the numbers together, and all the variables
-1y-2y(y-6)-9=0
We multiply parentheses
-2y^2-1y+12y-9=0
We add all the numbers together, and all the variables
-2y^2+11y-9=0
a = -2; b = 11; c = -9;
Δ = b2-4ac
Δ = 112-4·(-2)·(-9)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-7}{2*-2}=\frac{-18}{-4} =4+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+7}{2*-2}=\frac{-4}{-4} =1 $
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