2y-3(y+2)=10y-2(4-2y)

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Solution for 2y-3(y+2)=10y-2(4-2y) equation: 



2y-3(y+2)=10y-2(4-2y)

We move all terms to the left:

2y-3(y+2)-(10y-2(4-2y))=0

We add all the numbers together, and all the variables

2y-3(y+2)-(10y-2(-2y+4))=0

We multiply parentheses

2y-3y-(10y-2(-2y+4))-6=0



We calculate terms in parentheses: -(10y-2(-2y+4)), so:

10y-2(-2y+4)

We multiply parentheses

10y+4y-8

We add all the numbers together, and all the variables

14y-8

Back to the equation:

-(14y-8)



We add all the numbers together, and all the variables

-1y-(14y-8)-6=0

We get rid of parentheses

-1y-14y+8-6=0

We add all the numbers together, and all the variables

-15y+2=0

We move all terms containing y to the left, all other terms to the right

-15y=-2

y=-2/-15

y=2/15

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