2y-3(6y-5)=y+5(4y+11)

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Solution for 2y-3(6y-5)=y+5(4y+11) equation: 



2y-3(6y-5)=y+5(4y+11)

We move all terms to the left:

2y-3(6y-5)-(y+5(4y+11))=0

We multiply parentheses

2y-18y-(y+5(4y+11))+15=0



We calculate terms in parentheses: -(y+5(4y+11)), so:

y+5(4y+11)

We multiply parentheses

y+20y+55

We add all the numbers together, and all the variables

21y+55

Back to the equation:

-(21y+55)



We add all the numbers together, and all the variables

-16y-(21y+55)+15=0

We get rid of parentheses

-16y-21y-55+15=0

We add all the numbers together, and all the variables

-37y-40=0

We move all terms containing y to the left, all other terms to the right

-37y=40

y=40/-37

y=-1+3/37

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