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2y-3(2-3)+2=31
We move all terms to the left:
2y-3(2-3)+2-(31)=0
determiningTheFunctionDomain 2y+2-31-3(2-3)=0
We add all the numbers together, and all the variables
2y+2-31-3(-1)=0
We add all the numbers together, and all the variables
2y-26=0
We move all terms containing y to the left, all other terms to the right
2y=26
y=26/2
y=13
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