2y-2=12y+38

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Solution for 2y-2=12y+38 equation: 



2y-2=12y+38

We move all terms to the left:

2y-2-(12y+38)=0

We get rid of parentheses

2y-12y-38-2=0

We add all the numbers together, and all the variables

-10y-40=0

We move all terms containing y to the left, all other terms to the right

-10y=40

y=40/-10

y=-4

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