2y-2+2(3y+3)=-2(y+4)

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Solution for 2y-2+2(3y+3)=-2(y+4) equation: 



2y-2+2(3y+3)=-2(y+4)

We move all terms to the left:

2y-2+2(3y+3)-(-2(y+4))=0

We multiply parentheses

2y+6y-(-2(y+4))+6-2=0



We calculate terms in parentheses: -(-2(y+4)), so:

-2(y+4)

We multiply parentheses

-2y-8

Back to the equation:

-(-2y-8)



We add all the numbers together, and all the variables

8y-(-2y-8)+4=0

We get rid of parentheses

8y+2y+8+4=0

We add all the numbers together, and all the variables

10y+12=0

We move all terms containing y to the left, all other terms to the right

10y=-12

y=-12/10

y=-1+1/5

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