2y-12=4(y+2)

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Solution for 2y-12=4(y+2) equation: 



2y-12=4(y+2)

We move all terms to the left:

2y-12-(4(y+2))=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

2y-4y-8-12=0

We add all the numbers together, and all the variables

-2y-20=0

We move all terms containing y to the left, all other terms to the right

-2y=20

y=20/-2

y=-10

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