2y-1/2y+1-2y-7/y-3

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Solution for 2y-1/2y+1-2y-7/y-3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2*y-((1/2)*y)-(2*y)-(7/y)-3+1 = 0

2*y+(-1/2)*y-2*y-7*y^-1-3+1 = 0

-1/2*y^1-7*y^-1-2*y^0 = 0

(-1/2*y^2-2*y^1-7*y^0)/(y^1) = 0 // * y^2

y^1*(-1/2*y^2-2*y^1-7*y^0) = 0

y^1

(-1/2)*y^2-2*y-7 = 0

(-1/2)*y^2-2*y-7 = 0

DELTA = (-2)^2-(-7*4*(-1/2))

DELTA = -10

DELTA < 0

y in { } 

y belongs to the empty set

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