2y-(y+1)=y-1

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Solution for 2y-(y+1)=y-1 equation: 



2y-(y+1)=y-1

We move all terms to the left:

2y-(y+1)-(y-1)=0

We get rid of parentheses

2y-y-y-1+1=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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