2y-(2+4y)=32-2(4y-4)

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Solution for 2y-(2+4y)=32-2(4y-4) equation:


Simplifying
2y + -1(2 + 4y) = 32 + -2(4y + -4)
2y + (2 * -1 + 4y * -1) = 32 + -2(4y + -4)
2y + (-2 + -4y) = 32 + -2(4y + -4)

Reorder the terms:
-2 + 2y + -4y = 32 + -2(4y + -4)

Combine like terms: 2y + -4y = -2y
-2 + -2y = 32 + -2(4y + -4)

Reorder the terms:
-2 + -2y = 32 + -2(-4 + 4y)
-2 + -2y = 32 + (-4 * -2 + 4y * -2)
-2 + -2y = 32 + (8 + -8y)

Combine like terms: 32 + 8 = 40
-2 + -2y = 40 + -8y

Solving
-2 + -2y = 40 + -8y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8y' to each side of the equation.
-2 + -2y + 8y = 40 + -8y + 8y

Combine like terms: -2y + 8y = 6y
-2 + 6y = 40 + -8y + 8y

Combine like terms: -8y + 8y = 0
-2 + 6y = 40 + 0
-2 + 6y = 40

Add '2' to each side of the equation.
-2 + 2 + 6y = 40 + 2

Combine like terms: -2 + 2 = 0
0 + 6y = 40 + 2
6y = 40 + 2

Combine like terms: 40 + 2 = 42
6y = 42

Divide each side by '6'.
y = 7

Simplifying
y = 7

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