2y+4(3y-6)-2=32

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Solution for 2y+4(3y-6)-2=32 equation: 



2y+4(3y-6)-2=32

We move all terms to the left:

2y+4(3y-6)-2-(32)=0

We add all the numbers together, and all the variables

2y+4(3y-6)-34=0

We multiply parentheses

2y+12y-24-34=0

We add all the numbers together, and all the variables

14y-58=0

We move all terms containing y to the left, all other terms to the right

14y=58

y=58/14

y=4+1/7

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