2y+3=3(y+1)-2(4-2y)

Solution for 2y+3=3(y+1)-2(4-2y) equation:

2y+3=3(y+1)-2(4-2y)

We move all terms to the left:

2y+3-(3(y+1)-2(4-2y))=0

We add all the numbers together, and all the variables

2y-(3(y+1)-2(-2y+4))+3=0


We calculate terms in parentheses: -(3(y+1)-2(-2y+4)), so:

3(y+1)-2(-2y+4)

We multiply parentheses

3y+4y+3-8

We add all the numbers together, and all the variables

7y-5

Back to the equation:

-(7y-5)


We get rid of parentheses

2y-7y+5+3=0

We add all the numbers together, and all the variables

-5y+8=0

We move all terms containing y to the left, all other terms to the right

-5y=-8

y=-8/-5

y=1+3/5