2y+33=20+4y

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Solution for 2y+33=20+4y equation: 



2y+33=20+4y

We move all terms to the left:

2y+33-(20+4y)=0

We add all the numbers together, and all the variables

2y-(4y+20)+33=0

We get rid of parentheses

2y-4y-20+33=0

We add all the numbers together, and all the variables

-2y+13=0

We move all terms containing y to the left, all other terms to the right

-2y=-13

y=-13/-2

y=6+1/2

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