2y+32=3y-3

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Solution for 2y+32=3y-3 equation: 



2y+32=3y-3

We move all terms to the left:

2y+32-(3y-3)=0

We get rid of parentheses

2y-3y+3+32=0

We add all the numbers together, and all the variables

-1y+35=0

We move all terms containing y to the left, all other terms to the right

-y=-35

y=-35/-1

y=+35

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