2y+32=-2(y-2)

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Solution for 2y+32=-2(y-2) equation: 



2y+32=-2(y-2)

We move all terms to the left:

2y+32-(-2(y-2))=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

2y+2y-4+32=0

We add all the numbers together, and all the variables

4y+28=0

We move all terms containing y to the left, all other terms to the right

4y=-28

y=-28/4

y=-7

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