2y+3+12=34y

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Solution for 2y+3+12=34y equation:



2y+3+12=34y
We move all terms to the left:
2y+3+12-(34y)=0
We add all the numbers together, and all the variables
-32y+15=0
We move all terms containing y to the left, all other terms to the right
-32y=-15
y=-15/-32
y=15/32

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