2y+3(y-5)=20

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Solution for 2y+3(y-5)=20 equation: 



2y+3(y-5)=20

We move all terms to the left:

2y+3(y-5)-(20)=0

We multiply parentheses

2y+3y-15-20=0

We add all the numbers together, and all the variables

5y-35=0

We move all terms containing y to the left, all other terms to the right

5y=35

y=35/5

y=7

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