2y+3(y-4)=8y-5(y-10)

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Solution for 2y+3(y-4)=8y-5(y-10) equation:


Simplifying
2y + 3(y + -4) = 8y + -5(y + -10)

Reorder the terms:
2y + 3(-4 + y) = 8y + -5(y + -10)
2y + (-4 * 3 + y * 3) = 8y + -5(y + -10)
2y + (-12 + 3y) = 8y + -5(y + -10)

Reorder the terms:
-12 + 2y + 3y = 8y + -5(y + -10)

Combine like terms: 2y + 3y = 5y
-12 + 5y = 8y + -5(y + -10)

Reorder the terms:
-12 + 5y = 8y + -5(-10 + y)
-12 + 5y = 8y + (-10 * -5 + y * -5)
-12 + 5y = 8y + (50 + -5y)

Reorder the terms:
-12 + 5y = 50 + 8y + -5y

Combine like terms: 8y + -5y = 3y
-12 + 5y = 50 + 3y

Solving
-12 + 5y = 50 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-12 + 5y + -3y = 50 + 3y + -3y

Combine like terms: 5y + -3y = 2y
-12 + 2y = 50 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 + 2y = 50 + 0
-12 + 2y = 50

Add '12' to each side of the equation.
-12 + 12 + 2y = 50 + 12

Combine like terms: -12 + 12 = 0
0 + 2y = 50 + 12
2y = 50 + 12

Combine like terms: 50 + 12 = 62
2y = 62

Divide each side by '2'.
y = 31

Simplifying
y = 31

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