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2y+2=2(y+1)
We move all terms to the left:
2y+2-(2(y+1))=0
We calculate terms in parentheses: -(2(y+1)), so:We get rid of parentheses
2(y+1)
We multiply parentheses
2y+2
Back to the equation:
-(2y+2)
2y-2y-2+2=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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