2y+2.11/8y=190,y=40

Solution for 2y+2.11/8y=190,y=40 equation:

2y+2.11/8y=190.y=40

We move all terms to the left:

2y+2.11/8y-(190.y)=0


Domain of the equation: 8y!=0

y!=0/8

y!=0

y∈R


We add all the numbers together, and all the variables

2y+2.11/8y-(+190.y)=0

We get rid of parentheses

2y+2.11/8y-190.y=0

We multiply all the terms by the denominator


2y*8y-(190.y)*8y+2.11=0

We add all the numbers together, and all the variables

2y*8y-(+190.y)*8y+2.11=0

We multiply parentheses

-1520y^2+2y*8y+2.11=0

Wy multiply elements

-1520y^2+16y^2+2.11=0

We add all the numbers together, and all the variables

-1504y^2+2.11=0

a = -1504; b = 0; c = +2.11;
Δ = b2-4ac
Δ = 02-4·(-1504)·2.11
Δ = 12693.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12693.76}}{2*-1504}=\frac{0-\sqrt{12693.76}}{-3008}
=-\frac{\sqrt{}}{-3008}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12693.76}}{2*-1504}=\frac{0+\sqrt{12693.76}}{-3008}
=\frac{\sqrt{}}{-3008}
$