2y+2(y-5)=5(y+3)-4

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Solution for 2y+2(y-5)=5(y+3)-4 equation: 



2y+2(y-5)=5(y+3)-4

We move all terms to the left:

2y+2(y-5)-(5(y+3)-4)=0

We multiply parentheses

2y+2y-(5(y+3)-4)-10=0



We calculate terms in parentheses: -(5(y+3)-4), so:

5(y+3)-4

We multiply parentheses

5y+15-4

We add all the numbers together, and all the variables

5y+11

Back to the equation:

-(5y+11)



We add all the numbers together, and all the variables

4y-(5y+11)-10=0

We get rid of parentheses

4y-5y-11-10=0

We add all the numbers together, and all the variables

-1y-21=0

We move all terms containing y to the left, all other terms to the right

-y=21

y=21/-1

y=-21

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