2y+(3y-3)=17

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Solution for 2y+(3y-3)=17 equation: 



2y+(3y-3)=17

We move all terms to the left:

2y+(3y-3)-(17)=0

We get rid of parentheses

2y+3y-3-17=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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