2y+(3-y)=18-2(y+3)

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Solution for 2y+(3-y)=18-2(y+3) equation: 



2y+(3-y)=18-2(y+3)

We move all terms to the left:

2y+(3-y)-(18-2(y+3))=0

We add all the numbers together, and all the variables

2y+(-1y+3)-(18-2(y+3))=0

We get rid of parentheses

2y-1y-(18-2(y+3))+3=0



We calculate terms in parentheses: -(18-2(y+3)), so:

18-2(y+3)

determiningTheFunctionDomain
-2(y+3)+18

We multiply parentheses

-2y-6+18

We add all the numbers together, and all the variables

-2y+12

Back to the equation:

-(-2y+12)



We add all the numbers together, and all the variables

y-(-2y+12)+3=0

We get rid of parentheses

y+2y-12+3=0

We add all the numbers together, and all the variables

3y-9=0

We move all terms containing y to the left, all other terms to the right

3y=9

y=9/3

y=3

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