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2y*y=152
We move all terms to the left:
2y*y-(152)=0
Wy multiply elements
2y^2-152=0
a = 2; b = 0; c = -152;
Δ = b2-4ac
Δ = 02-4·2·(-152)
Δ = 1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1216}=\sqrt{64*19}=\sqrt{64}*\sqrt{19}=8\sqrt{19}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{19}}{2*2}=\frac{0-8\sqrt{19}}{4} =-\frac{8\sqrt{19}}{4} =-2\sqrt{19} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{19}}{2*2}=\frac{0+8\sqrt{19}}{4} =\frac{8\sqrt{19}}{4} =2\sqrt{19} $
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