2y*y-2=3y

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Solution for 2y*y-2=3y equation:



2y*y-2=3y
We move all terms to the left:
2y*y-2-(3y)=0
We add all the numbers together, and all the variables
-3y+2y*y-2=0
Wy multiply elements
2y^2-3y-2=0
a = 2; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·2·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*2}=\frac{-2}{4} =-1/2 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*2}=\frac{8}{4} =2 $

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