2y(y+1)=2y+32

Solution for 2y(y+1)=2y+32 equation:

Simplifying
2y(y + 1) = 2y + 32

Reorder the terms:
2y(1 + y) = 2y + 32
(1 * 2y + y * 2y) = 2y + 32
(2y + 2y2) = 2y + 32

Reorder the terms:
2y + 2y2 = 32 + 2y

Add '-2y' to each side of the equation.
2y + -2y + 2y2 = 32 + 2y + -2y

Combine like terms: 2y + -2y = 0
0 + 2y2 = 32 + 2y + -2y
2y2 = 32 + 2y + -2y

Combine like terms: 2y + -2y = 0
2y2 = 32 + 0
2y2 = 32

Solving
2y2 = 32

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '2'.
y2 = 16

Simplifying
y2 = 16

Take the square root of each side:
y = {-4, 4}