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2y(3y+5)=y
We move all terms to the left:
2y(3y+5)-(y)=0
We add all the numbers together, and all the variables
-1y+2y(3y+5)=0
We multiply parentheses
6y^2-1y+10y=0
We add all the numbers together, and all the variables
6y^2+9y=0
a = 6; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·6·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*6}=\frac{-18}{12} =-1+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*6}=\frac{0}{12} =0 $
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