2y(3+4y)=0

Solution for 2y(3+4y)=0 equation:

2y(3+4y)=0

We add all the numbers together, and all the variables

2y(4y+3)=0

We multiply parentheses

8y^2+6y=0

a = 8; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·8·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*8}=\frac{-12}{16}
=-3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*8}=\frac{0}{16}
=0
$