2y(3+4)1y(5+4)=

Solution for 2y(3+4)1y(5+4)= equation:

Simplifying
2y(3 + 4) * 1y(5 + 4) = 0

Combine like terms: 3 + 4 = 7
2y(7) * 1y(5 + 4) = 0

Combine like terms: 5 + 4 = 9
2y * 7 * 1y(9) = 0

Reorder the terms for easier multiplication:
2 * 7 * 1 * 9y * y = 0

Multiply 2 * 7
14 * 1 * 9y * y = 0

Multiply 14 * 1
14 * 9y * y = 0

Multiply 14 * 9
126y * y = 0

Multiply y * y
126y2 = 0

Solving
126y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '126'.
y2 = 0

Simplifying
y2 = 0

Take the square root of each side:
y = {0}