2y(2)=y+5

Solution for 2y(2)=y+5 equation:

2y(2)=y+5

We move all terms to the left:

2y(2)-(y+5)=0

We add all the numbers together, and all the variables

2y^2-(y+5)=0

We get rid of parentheses

2y^2-y-5=0

We add all the numbers together, and all the variables

2y^2-1y-5=0

a = 2; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·2·(-5)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{41}}{2*2}=\frac{1-\sqrt{41}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{41}}{2*2}=\frac{1+\sqrt{41}}{4}
$