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2x=x(x+2)
We move all terms to the left:
2x-(x(x+2))=0
We calculate terms in parentheses: -(x(x+2)), so:We get rid of parentheses
x(x+2)
We multiply parentheses
x^2+2x
Back to the equation:
-(x^2+2x)
-x^2+2x-2x=0
We add all the numbers together, and all the variables
-1x^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-2}=0$
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