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2x=96/x
We move all terms to the left:
2x-(96/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+96/x)=0
We get rid of parentheses
2x-96/x=0
We multiply all the terms by the denominator
2x*x-96=0
Wy multiply elements
2x^2-96=0
a = 2; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·2·(-96)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*2}=\frac{0-16\sqrt{3}}{4} =-\frac{16\sqrt{3}}{4} =-4\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*2}=\frac{0+16\sqrt{3}}{4} =\frac{16\sqrt{3}}{4} =4\sqrt{3} $
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