2x=8+62/3x

Solution for 2x=8+62/3x equation:

2x=8+62/3x

We move all terms to the left:

2x-(8+62/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(62/3x+8)=0

We get rid of parentheses

2x-62/3x-8=0

We multiply all the terms by the denominator


2x*3x-8*3x-62=0

Wy multiply elements

6x^2-24x-62=0

a = 6; b = -24; c = -62;
Δ = b2-4ac
Δ = -242-4·6·(-62)
Δ = 2064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2064}=\sqrt{16*129}=\sqrt{16}*\sqrt{129}=4\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{129}}{2*6}=\frac{24-4\sqrt{129}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{129}}{2*6}=\frac{24+4\sqrt{129}}{12}
$