2x=3x+10-2(x-1)

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Solution for 2x=3x+10-2(x-1) equation: 



2x=3x+10-2(x-1)

We move all terms to the left:

2x-(3x+10-2(x-1))=0



We calculate terms in parentheses: -(3x+10-2(x-1)), so:

3x+10-2(x-1)

determiningTheFunctionDomain
3x-2(x-1)+10

We multiply parentheses

3x-2x+2+10

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

2x-x-12=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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