2x=1/3x+10

Solution for 2x=1/3x+10 equation:

2x=1/3x+10

We move all terms to the left:

2x-(1/3x+10)=0


Domain of the equation: 3x+10)!=0

x∈R


We get rid of parentheses

2x-1/3x-10=0

We multiply all the terms by the denominator


2x*3x-10*3x-1=0

Wy multiply elements

6x^2-30x-1=0

a = 6; b = -30; c = -1;
Δ = b2-4ac
Δ = -302-4·6·(-1)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{231}}{2*6}=\frac{30-2\sqrt{231}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{231}}{2*6}=\frac{30+2\sqrt{231}}{12}
$