2x2=248

Solution for 2x2=248 equation:

2x^2=248

We move all terms to the left:

2x^2-(248)=0

a = 2; b = 0; c = -248;
Δ = b2-4ac
Δ = 02-4·2·(-248)
Δ = 1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1984}=\sqrt{64*31}=\sqrt{64}*\sqrt{31}=8\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{31}}{2*2}=\frac{0-8\sqrt{31}}{4}
=-\frac{8\sqrt{31}}{4}
=-2\sqrt{31}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{31}}{2*2}=\frac{0+8\sqrt{31}}{4}
=\frac{8\sqrt{31}}{4}
=2\sqrt{31}
$