2x2=102x=5

Solution for 2x2=102x=5 equation:

2x^2=102x=5

We move all terms to the left:

2x^2-(102x)=0

a = 2; b = -102; c = 0;
Δ = b2-4ac
Δ = -1022-4·2·0
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-102}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+102}{2*2}=\frac{204}{4}
=51
$