2x2/3x=14

Solution for 2x2/3x=14 equation:

2x^2/3x=14

We move all terms to the left:

2x^2/3x-(14)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


2x^2-14*3x=0

Wy multiply elements

2x^2-42x=0

a = 2; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·2·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*2}=\frac{84}{4}
=21
$