2x2-x-528=0

Solution for 2x2-x-528=0 equation:

2x^2-x-528=0

We add all the numbers together, and all the variables

2x^2-1x-528=0

a = 2; b = -1; c = -528;
Δ = b2-4ac
Δ = -12-4·2·(-528)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-65}{2*2}=\frac{-64}{4}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+65}{2*2}=\frac{66}{4}
=16+1/2
$