2x2-8x+54=(x-7)2

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Solution for 2x2-8x+54=(x-7)2 equation: 



2x^2-8x+54=(x-7)2

We move all terms to the left:

2x^2-8x+54-((x-7)2)=0



We calculate terms in parentheses: -((x-7)2), so:

(x-7)2

We multiply parentheses

2x-14

Back to the equation:

-(2x-14)



We get rid of parentheses

2x^2-8x-2x+14+54=0

We add all the numbers together, and all the variables

2x^2-10x+68=0

a = 2; b = -10; c = +68;
Δ = b2-4ac
Δ = -102-4·2·68
Δ = -444
Delta is less than zero, so there is no solution for the equation

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