2x2-780x+44600=0

Solution for 2x2-780x+44600=0 equation:

2x^2-780x+44600=0

a = 2; b = -780; c = +44600;
Δ = b2-4ac
Δ = -7802-4·2·44600
Δ = 251600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{251600}=\sqrt{400*629}=\sqrt{400}*\sqrt{629}=20\sqrt{629}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-780)-20\sqrt{629}}{2*2}=\frac{780-20\sqrt{629}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-780)+20\sqrt{629}}{2*2}=\frac{780+20\sqrt{629}}{4}
$