2x2-720x+25600=0

Solution for 2x2-720x+25600=0 equation:

2x^2-720x+25600=0

a = 2; b = -720; c = +25600;
Δ = b2-4ac
Δ = -7202-4·2·25600
Δ = 313600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{313600}=560$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-720)-560}{2*2}=\frac{160}{4}
=40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-720)+560}{2*2}=\frac{1280}{4}
=320
$