2x2-67x-105=0

Solution for 2x2-67x-105=0 equation:

2x^2-67x-105=0

a = 2; b = -67; c = -105;
Δ = b2-4ac
Δ = -672-4·2·(-105)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-73}{2*2}=\frac{-6}{4}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+73}{2*2}=\frac{140}{4}
=35
$