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2x^2-5x+10x=4
We move all terms to the left:
2x^2-5x+10x-(4)=0
We add all the numbers together, and all the variables
2x^2+5x-4=0
a = 2; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·2·(-4)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{57}}{2*2}=\frac{-5-\sqrt{57}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{57}}{2*2}=\frac{-5+\sqrt{57}}{4} $
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