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2x^2-50x+288=0
a = 2; b = -50; c = +288;
Δ = b2-4ac
Δ = -502-4·2·288
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-14}{2*2}=\frac{36}{4} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+14}{2*2}=\frac{64}{4} =16 $
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