2x2-46x-1140=0

Solution for 2x2-46x-1140=0 equation:

2x^2-46x-1140=0

a = 2; b = -46; c = -1140;
Δ = b2-4ac
Δ = -462-4·2·(-1140)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-106}{2*2}=\frac{-60}{4}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+106}{2*2}=\frac{152}{4}
=38
$