If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-3x-65=0
a = 2; b = -3; c = -65;
Δ = b2-4ac
Δ = -32-4·2·(-65)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-23}{2*2}=\frac{-20}{4} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+23}{2*2}=\frac{26}{4} =6+1/2 $
| 4x^2-20x+2=26 | | 4x=356 | | 3x-40=x=180 | | 9-7(x+8)=x | | 2x²+9x-45=0 | | (11x+1)/(x^2+3x+2)=x | | -3x+1=x-17 | | 4|x+2|+5=x | | ×^2+3x-154=0 | | -2(x-3)=-6+2x | | 9^x+27(3^x-3)-42=0 | | 1.1x-2.3=0.6x-1.65 | | y^2=7-6y | | 7p=3p+20 | | 3/2x-4=10 | | 15xx10=2000 | | 2x^2+16×+11=0 | | 0.5(10x-4)=-0.5(-8x-2) | | 3^2a-9=243 | | 8x^2+10=74 | | 1/2x=9/2x+10 | | 4x+256=0 | | 3+2=x4 | | 1/4^x+4=8 | | 1.08x=350 | | x/3(x+4)=39 | | (x+8)/16=(5/8)+(x-3)/2 | | x+8/16=5/8+x-3/2 | | 26-(3+9y-4(y+5))=-5(5y-7)-(6(y-1)-20y+22) | | 80x^2-2x-3=0 | | 3m2-7m+4=0 | | -15.79−18.9w=-8.4w−7.9w+18.79 |