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2x^2-3x+4=-(x-1)2-6
We move all terms to the left:
2x^2-3x+4-(-(x-1)2-6)=0
We calculate terms in parentheses: -(-(x-1)2-6), so:We get rid of parentheses
-(x-1)2-6
We multiply parentheses
-2x+2-6
We add all the numbers together, and all the variables
-2x-4
Back to the equation:
-(-2x-4)
2x^2-3x+2x+4+4=0
We add all the numbers together, and all the variables
2x^2-1x+8=0
a = 2; b = -1; c = +8;
Δ = b2-4ac
Δ = -12-4·2·8
Δ = -63
Delta is less than zero, so there is no solution for the equation
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