2x2-20x+100=8

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Solution for 2x2-20x+100=8 equation: 



2x^2-20x+100=8

We move all terms to the left:

2x^2-20x+100-(8)=0

We add all the numbers together, and all the variables

2x^2-20x+92=0

a = 2; b = -20; c = +92;
Δ = b2-4ac
Δ = -202-4·2·92
Δ = -336
Delta is less than zero, so there is no solution for the equation

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